[Building Sakai] Get user session

[Steve Swinsburg]

Hi Wellington,

To get the current userId:
sessionManager.getCurrentSessionUserId();
This will be a Sakai userId, you might need to translate it into an  
eid for use in other systems. See UserDirectoryService to get an eid  
from a userid via a User object. Alternatively you can get a Session  
object from the SessionManager and get the eid from that.

You'll need to inject the SessionManager API into your service via  
Spring or use the ComponentManager to get it for you.

If you have the full source, issue mvn javadoc:javadoc - 
Daggregate=true (or just mvn javadoc:aggregate) to get the docs. You  
might need to repeat for the Kernel source since most core API's live  
there.

cheers,
Steve



On 05/11/2009, at 11:09 PM, Wellington Santos wrote:

> Hi everyone,
>
> I need get the id of user who is logged in Sakai.
> Example: I have my application that will get the user and that user  
> will be logged by Sakai web page login and after he/she will select  
> a link and that link redirect it to my application, so when my  
> application is called I'll get the user id, and after I'll call  
> another application passing more informations by post method. Is  
> there any way to make it? If so, how can I do? Could you send me an  
> example?
>
>
> Best Regards,
>
>
> Wellington Santos
> Analyst and Integrator of System
> People Brasil Educação
> Campinas - SP - Brazil
> msn: wbsantos at hotmail.com
> skype: wellington.deh
> +55 (19) 4062-9750
> +55 (11) 3777-4038
>
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